Monday, October 25, 2010

Module 2_Measurments and Error Analysis

Dear Students
The diameter of a wire was measured by a group of students with a micrometer, and the following readings were recorded:
2.65, 2.64 , 2.63 , 2.69, 2.66 , 2.7 , 2.71, 2.62 , 2.62 , 2.60

Calculate
  • the average
  • the standard deviation
  • calculate the accuracy, if the true value is 2.65.
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9 comments:

  1. UnknownOctober 27, 2010 at 8:48 PM

    The average is
    (2.65+2.64+2.63+2.69+2.66+2.7+2.71+2.62+2.62+2.60)/10 = 2.652
    The standard deviation is
    √26.52/9=1.72
    Accuracy
    (|2.652-2.65|/2.65)x100 = 0.00076%
    SAEED TALAL 11-03

    ReplyDelete
  2. UnknownOctober 27, 2010 at 9:57 PM

    The average is
    (2.65+2.64+2.63+2.69+2.66+2.7+2.71+2.62+2.62+2.60)/10 = 2.652

    The standard deviation is
    √26.52/9=1.72
    Accuracy
    (|2.652-2.65|/2.65)x100 = 0.00076%

    Abdulrhman Abdullah Al Marzouqi
    11 - 02

    ReplyDelete
  3. osama2026October 28, 2010 at 3:07 AM

    Osama Zaid Abdullah
    11-03

    1)average=(2.65+2.64+2.63+2.69+2.66+ 2.7+2.71+2.62+2.62+2.60)/10=2.652

    2)Standard deviation= σ = √sum/(n-1)= √ (26.52/9)= 1.71659

    3) Accuracy=(|2.60-2.65|/2.65)x100%=0.019%

    ReplyDelete
  4. abdulla ALameriOctober 28, 2010 at 3:13 AM

    The average is
    (2.65+2.64+2.63+2.69+2.66+2.7+2.71+2.62+2.62+2.60)/10 = 2.652

    The standard deviation is
    √26.52/9=1.72
    Accuracy
    (|2.652-2.65|/2.65)x100 = 0.00076%

    Abdulla Khames ALameri

    11-03

    ReplyDelete
  5. UnknownOctober 28, 2010 at 3:21 AM

    1* Average=(2.65+2.64+2.63+2.69+2.66+ 2.7+2.71+2.62+2.62+2.60)/10=2.652

    2* Standard deviation= σ = √sum/(n-1)= √ (26.52/9)= 1.71659

    3*Accuracy=(|2.61-2.65|/2.65)x100%=0.02149%

    >>> Sultan Abdulla Alqubaisi <<<
    ((( 11-03 )))
    ID: 1011090143

    ReplyDelete
  6. UnknownOctober 28, 2010 at 3:25 AM

    A) Average = (2.65+2.64+2.63+2.69+2.66+2.7+2.71+2.62+2.62+2.60)/10=2.652

    B) Standard deviation= σ = √sum/(n-1)= √ (26.52/9)= 1.72

    C) Accuracy=(|2.60-2.65|/2.65)x100%=0.02%

    Mohammed Khalid Almeraikhi

    11-03 ID: 90217

    ReplyDelete
  7. UnknownDecember 30, 2010 at 1:56 AM

    The average is:
    (2.65+2.64+2.63+2.69+2.66+2.7+2.71+2.62+2.62+2.60)/10 = 2.652
    The standard deviation is
    √26.52/9=1.72
    Accuracy:
    (|2.652-2.65|/2.65)x100 = 0.00076%

    Talal al hamily 11-03

    ReplyDelete
  8. UnknownDecember 30, 2010 at 2:17 AM

    A) Average = (2.65+2.64+2.63+2.69+2.66+2.7+2.71+2.62+2.62+2.60)/10=2.652

    B) Standard deviation= σ = √sum/(n-1)= √ (26.52/9)= 1.72

    C) Accuracy=(|2.60-2.65|/2.65)x100%=0.02%

    Awad Juma 11-3

    ReplyDelete
  9. UnknownJanuary 2, 2011 at 9:02 AM

    A) Average = (2.65+2.64+2.63+2.69+2.66+2.7+2.71+2.62+2.62+2.60)/10=2.652

    B) Standard deviation= σ = √sum/(n-1)= √ (26.52/9)= 1.72

    C) Accuracy=(|2.60-2.65|/2.65)x100%=0.02%



    rashed 11-03

    ReplyDelete

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